Apollonius's theorem

In geometry, Apollonius's theorem is a theorem relating the length of a median of a triangle to the lengths of its sides. It states that "the sum of the squares of any two sides of any triangle equals twice the square on half the third side, together with twice the square on the median bisecting the third side".

Apollonius's theorem

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Relates the length of a median of a triangle to the lengths of its sides
This article is about the lengths of the sides of a triangle. For his work on circles, see Problem of Apollonius.
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Pythagoras as a special case:
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In geometry, Apollonius's theorem is a theorem relating the length of a median of a triangle to the lengths of its sides.
It states that "the sum of the squares of any two sides of any triangle equals twice the square on half the third side, together with twice the square on the median bisecting the third side".

Specifically, in any triangle

A B C , {displaystyle ABC,}

"{displaystyle if

A D {displaystyle AD}

"AD" is a median, then

| A B | 2 + | A C | 2 = 2 ( | A D | 2 + | B D | 2 ) . {displaystyle |AB|^{2}+|AC|^{2}=2left(|AD|^{2}+|BD|^{2}right).}

"{displaystyle

It is a special case of Stewart's theorem. For an isosceles triangle with

| A B | = | A C | , {displaystyle |AB|=|AC|,}

"{displaystyle the median

A D {displaystyle AD}

"AD" is perpendicular to

B C {displaystyle BC}

"BC" and the theorem reduces to the Pythagorean theorem for triangle

A D B {displaystyle ADB}

"{displaystyle (or triangle

A D C {displaystyle ADC}

"{displaystyle). From the fact that the diagonals of a parallelogram bisect each other, the theorem is equivalent to the parallelogram law.

The theorem is named for the ancient Greek mathematician Apollonius of Perga.

Proof[]

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Proof of Apollonius's theorem

The theorem can be proved as a special case of Stewart's theorem, or can be proved using vectors (see parallelogram law). The following is an independent proof using the law of cosines.[1]

Let the triangle have sides

a , b , c {displaystyle a,b,c}

"a,b,c" with a median

d {displaystyle d}

"d" drawn to side

a . {displaystyle a.}

"a." Let

m {displaystyle m}

"m" be the length of the segments of

a {displaystyle a}

"a" formed by the median, so

m {displaystyle m}

"m" is half of

a . {displaystyle a.}

"a." Let the angles formed between

a {displaystyle a}

"a" and

d {displaystyle d}

"d" be

θ {displaystyle theta }

"theta and

θ , {displaystyle theta ^{prime },}

"{displaystyle where

θ {displaystyle theta }

"theta includes

b {displaystyle b}

"b" and

θ {displaystyle theta ^{prime }}

"theta^{prime}" includes

c . {displaystyle c.}

"c." Then

θ {displaystyle theta ^{prime }}

"theta^{prime}" is the supplement of

θ {displaystyle theta }

"theta and

cos θ = cos θ . {displaystyle cos theta ^{prime }=-cos theta .}

"{displaystyle The law of cosines for

θ {displaystyle theta }

"theta and

θ {displaystyle theta ^{prime }}

"theta^{prime}" states that

b 2 = m 2 + d 2 2 d m cos θ c 2 = m 2 + d 2 2 d m cos θ = m 2 + d 2 + 2 d m cos θ . {displaystyle {begin{aligned}b^{2}&=m^{2}+d^{2}-2dmcos theta \c^{2}&=m^{2}+d^{2}-2dmcos theta '\&=m^{2}+d^{2}+2dmcos theta .,end{aligned}}}

"{displaystyle

Add the first and third equations to obtain

b 2 + c 2 = 2 ( m 2 + d 2 ) {displaystyle b^{2}+c^{2}=2(m^{2}+d^{2})}

"{displaystyle

as required.

See also[]

References[]

  1. ^

    Godfrey, Charles; Siddons, Arthur Warry (1908). Modern Geometry. University Press. p. 20.

External links[]


Si quieres conocer otros artículos parecidos a Apollonius's theorem puedes visitar la categoría Euclidean geometry.

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